lambda = 4 /hr.
mu = 60/20 = 3 per hr.
utilization (rho) = lambda /mu x no. of servers = 4/3×3 = 4/9
time spent in queue = lambda /m x [( rho)n / 1-rho]
Where n = ( 2m+2)0.5 -1 where m = no. of servers
n = (2×3 +2)0.5 -1 = (8)0.5 -1 = 1.82
T= Time spent in queue = 4/3 x [ (4/9)1.82 / 1-4/9] = 4/3 [ 0.228/ 0.555] = 0.54 hour
Ca = S.D. /Avg = 60/20 = 3
Cs = 15/15 = 1
Effective time = T x ( Ca2 + Cs2) /2 = T x ( 9+1)/2 = 5T = 5×0.54 hr = 2.7 hr. = 162 min.